# 输出前十个斐波那契数列的值
# 知识点：递归


def fib(n):
    if n == 1:
        return [1]
    if n == 2:
        return [1, 1]
    fibs = [1, 1]
    for i in range(2, n):
        fibs.append(fibs[i-1] + fibs[i-2])
    return fibs


print(fib(10))